哈尔滨理工大学 应用科学学院,黑龙江,哈尔滨,150080
纸质出版:2019
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王学仁. 爱因斯坦场方程研究[J]. 哈尔滨理工大学学报, 2019,24(1):145-149.
WANG Xue-ren. A Study of Einstein Field Equation[J]. 2019, 24(1): 145-149.
王学仁. 爱因斯坦场方程研究[J]. 哈尔滨理工大学学报, 2019,24(1):145-149. DOI: 10.15938/j.jhust.2019.01.024.
WANG Xue-ren. A Study of Einstein Field Equation[J]. 2019, 24(1): 145-149. DOI: 10.15938/j.jhust.2019.01.024.
摘要:我们将介绍我们的工作:①把9个关联系数分成两组:涉及(线加速度)的A组包括Γ001
Γ100
Γ111
Γ122
和 Γ133;不涉及的B组包括Γ212
Γ233
Γ313
和 Γ323。②回顾关系式()r=()Nγ3,这里()r是相对论力学中的线加速度,()N是牛顿力学中的线加速度,γ是洛伦兹因数。③我们已经确定(Γ001)N=-b′b-1
(Γ100)N=-c2b′b-5
(Γ111)N=b′b-1
(Γ122)N=-rb-2
(Γ133)N=-rb-2sin2θ。④我们已经确定(Γ001)r=(-b′b-1)γ3
(Γ100)r=(-c2b′b-5)γ3
(Γ111)r=(b′b-1)γ3
(Γ122)r=(-rb-2)γ3
(Γ133)r=(-rb-2sin2θ)γ3。⑤我们已经证明Γ001=A′/(2A)=-b′b-1
Γ100=A′/(2B)=-c2b′b-5
Γ111=b′/(2B)=b′b-1
Γ122=-rb-1=-rb-2
Γ133=-rb-1sin2θ=-rb-2sin2θ。(6)我们已经确定(Γ112)Nr=r-1
(Γ233)Nr=sinθcosθ
(Γ313)Nr=r-1
(Γ323)Nr=cotθ。⑥我们分析了Schwarzschild解并得出两个结论:(a)B =(1-2GM/(c2r))-1=(1-r2/c2)-1=γ2,这表明它和牛顿守恒定律有关。(b)对于弱引力场GM/(c2r)1
B=(1-2GM/(c2r))-1≈1+2GM/(c2r)≈1+2GM/(c2r)+(GM/(c2r))2=(1+GM/(c2r))2=γ2
因此
γ=1+GM/(c2r)=b,这个关系式对强引力场也适用。把这些需要的表达方式带入方程式,并应用关系式,我们能简化方程式。我们已经得到了相对论解:-c2dτ2=c2(1+GM/(c2r))-2dt2-(1+GM/(c2r))2dr2-r2dθ2-r2sin2θdφ2.
Abstract:In this paper we present our research work: ①We divide 9 connection coefficients into two groups: Group Ainvolving (the linear acceleration)includes Γ001
Γ100
Γ111
Γ122
and Γ133; Group B not involving includes Γ212
Γ233
Γ313
and Γ323. ②Recalling the relation formula: ()R=()Nγ3
where ()R is the linearacceleration in relativistic mechanics
()N the linear acceleration inNewtoneon mechanics
and γ Lorrentz factor. ③Wehave determined that (Γ001)N= -b′b-1
(Γ100)N= -c2b′b-5
(Γ111)N= b′b-1
(Γ122)N=-rb-2
(Γ133)N= -rb-2sin2θ. ④We havedetermined that (Γ001)R = (-b′b-1)γ3
(Γ100)R = (-c2b′b-5)γ3
(Γ111)R = (b′b-1)γ3
(Γ122)R = (-rb-2)γ3
(Γ133)R = (-rb-2sin2θ)γ3. ⑤Wehave proved that Γ001=A′/(2A)=-b′b-1
Γ100 = A′/(2B) = -c2b′b-5
Γ111 = B′/(2B)= b′b-1
Γ122 = -rB-1 = -rb-2
Γ133 = -rB-1sin2θ= -rb-2sin2θ. (6)We havedetermined that (Γ112)NR = r-1
(Γ233)NR = sinθcosθ
(Γ313)NR= r-1
(Γ323)NR = cotθ.⑥We have analyzed Schwarzschild solution
anddrawn two conclusions: (a)B=(1-2GM/(c2r))-1 = (1-r2/c2)-1 =γ2
indicating that it involves Newtoneon formula of energy conservation. (b)Inthe case of the weak gravitational field
GM/(c2r)1
B = (1-2GM/(c2r))-1 ≈ 1 +2GM/(c2r) ≈ 1 + 2GM/(c2r) + (GM/(c2r))2 = (1+GM/(c2r))2 = γ2
therefore
γ= 1 +GM/(c2r) = b
it holds too
in the case of the strong gravitational field.(8)Substituting the needed expressions into equations
and applying therelation formulas
we can simplify the equations
Obtaining the relativisticsolution:-c2dτ2 = c2(1+GM/(c2r))-2dt2 - (1+GM/(c2r))2dr2-r2dθ2-r2sin2θdφ2
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